UNIX for Advanced & Expert Users

Hi Everybody,

I want to create a shell script named as say "jip" and it is runned.
And i want that when i do ps + grep for the process than this jip should be shown as process.

Infact there might be process with name jip which is already running.

ps -ef |grep jip>/dev/null /* finds if there is one whith no verbose */
if [ $? -ne 0 ] /* if there is not executes jip */
then
jip
fi

Infact i didn't get you.
My concern is to create a simple shell script name say "jip".
Ofcourse there are other jip process which are running in the background.which are generally stopped by another shell script (say stop.sh).

My concern is to check for multiple jip process which are left running even after "stop.sh" is executed.
So i want to change the stop.sh but inorder to visualize whether the modification is working fine or not, i have to check it .And this can be achieved if only there are multiple jip process.

So i want to create a shell script which when runned should be viewed in the ps + grep of jip.

But i am not been able to do it.

I have created a file with the name jip.sh, where an infinite loop is running, but then also it is not viewed when i do grep for the "jip" process.

Can u please help me out from this. ?

As much as I understood .You want to see your background process named something with ps ;

ps -ef |grep processname gives this.

there is no need to infinite loop. just;

echo "input someting : \n "
read input1
echo $input1

untill you input anything process waits.when you enter finishes.while waiting input you can check the process in on other screen. and you can start multiple processes.