UNIX for Advanced & Expert Users

Hi,

Can anybody throw somelight on how to handle date in a shell script?

I need to pass the date in this format 'yymmdd' and then pad it to a file.

The way in which i've handled is given below, but the date is not getting passed rather the file is getting created with a null date. Any expert suggestions to handle this will be much appreciated. Thanks!

DT=date -u '070101' + "%y%m%d"

FILE=XYZ
export OUT1=$TMP/${FILE}_rbm_${DT}_01.txt
export OUT3=$TMP/${FILE}_rbm_${DT}_01.txt.ctl
FILE=123
export OUT2=$TMP/${FILE}_rbm_${DT}_02.txt
export OUT4=$TMP/${FILE}_rbm_${DT}_02.txt.ctl

I think,
'date -u '070101' + "%y%m%d"' | read DT
will work.


erol

Perhaps this ?

Code:

date -u -d '070101' +"%y%m%d"