UNIX for Advanced & Expert Users

Hi,

Thanks for your reply.

I found the mistake. You dont take the data I have given, instead make a "ls -l > file1" and try with

Code:

cat file1 | awk -F"[ /]" ' { print $5 "," $NF } '

It does not give the desired output. becuase between $1 and $2 there are many spaces, that is why it takes as different columns. Since the size of the file varies I can not take a fixed column.

Is there a way for this

Ronald.

Code:

sed 's;.*/;;' input_file

Hi,

Its worked perfectly.

Along with that, i want the Size column also.
like
1036695,9565DW07.04B
124080,2082DW07.04B

Ronald.

Code:

awk '{print $NF,$5}' <file-name>|cut -d"/" -f3|awk '{print $2 "," $1}'

Hi everybody,

I could make it work like this.

Code:

ls -l `find . -name *DW07.04B -print` | sed "s/ *[ ]/ /g" | awk -F"[ /]" ' { print $5 "," $NF } ' > file3

Thanks everybody.

Ronald.

Ronald,
Next time, try to specify all requirements at first.
A lot of times, a so called 'simple' change can mean a total rewrite
or complication of the solution.