UNIX for Advanced & Expert Users

Thanks Madan,

I had done this but now I am working on date math to find out the 60 days ago dates it should delete as compared to the lateset file which was 2007-01-13, which means 13-october-2006... any ideas

datecalc i dont have

bash-2.03$ datecalc
bash: datecalc: command not found

bash-2.03$ /bin/datecalc
bash: /bin/datecalc: No such file or directory

datecalc is not a command

its a script that is available handy in our forums - search for datecalc

The full script for datacalc is posted at the link I provided.

Yes , I saw that ....

I am not able to understand how this datecalc can be included with our needs

You copy the datacalc script to your system.

From with in you script you next can call this script like you call any other command or script.

Again, Suppose your most recent log file is from Jan 28, 2007

In your script:

JDATE=`<path to location of datacalc>/datacalc -j 2007 01 28`

The variable JDATE will now hold the Julian Date representation of Jan 28, 2007.

A Julian date is a single number

Next you substract the 60 day.

((JDATE=${JDATE}-60))

You connvert the Julian Date back to the regualar date format

REGDATE=`<path to location of datacalc>/datacalc -j ${JDATE}`

The variable REGDATE will now hold the string "2006 11 29"