How to evaluate expression under awk?

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I have a txt file like below: testin.txt AB BC CD DE I have the following awk script BEGIN {flag1="N"} /(AB)|(BC)|(CD)|(DE)/ {flag1="Y"} END {print flag1} >awk -f testin.awk testin.txt Returns Y

LEARN ABOUT DEBIAN

today

mhc(1)							      General Commands Manual							    mhc(1)

NAME

       today - Show your today's schedules.

SYNOPSIS

       today [options]

DESCRIPTION

       This  manual  page  documents  briefly  the today commands.  This manual page was written for the Debian GNU/Linux distribution because the
       original program does not have a manual page.

       today is a program that show your schedules in MHC repository.

OPTIONS

       A summary of options is included below.

       -h, --help
	      Show summary of options.

       --format=FORMAT
	      change output format.  FORMAT is 'html' or 'ps.

       --category=CATEGORY
	      Pick only in CATEGORY. '!' and space separated multiple values are allowed.

       --date=strig[+n]
	      Set a period of date. String is one of these: today, tomorrow, sun ... sat, yyyymmdd, yyyymm.  yyyymm lists all days in  the  month.
	      list n+1 days of schedules if +n is given.  default value is 'today+0'

       --mail=ADDRESS
	      Send a e-mail to ADDRESS instead of listing to stdout

SEE ALSO

       adb2mhc(1), gemcal(1), mhc-scan(1), mhc2palm(1), palm2mhc(1), mhc(5).

AUTHOR

       This  program  was  written by Yoshinari Nomura <nom@quickhack.net> and this manual page was written by Fumitoshi UKAI <ukai@debian.or.jp>,
       for the Debian GNU/Linux system (but may be used by others).

								    23 Jun 2000 							    mhc(1)

UNIX for Advanced & Expert Users