UNIX for Advanced & Expert Users

i want to print the data between two line numbers in file to another file.
which command should i use

i tried sed command . i am storing the line numbers in two variables say L1,L2. but $L1 and $L2 are not working in sed command.

is there any other command to do this
reply soon

What sed command did you try ?

hey i got the solution to the above problem.

i used the sed command sed -n " $L1,$L2 w outfile" inputfile where L1 and L2 are variables which contains line numbers.

previously i used the same command but with ' qoutes instead of " quotes.


Any have thanks for showing interest to solve my problem

i am using sed -n "$lineno1 $lineno2 w OUT.FILE" $infile , but i got the error

sed: -e expression #1, char 3: Unknown command: `1'

please help

Try with awk:

cat -n test.log | awk '{if((NR>122)&&(NR<128)) print}'

for a test to see if it is working (this should print the lines from number 123 to 127. Then you can remove 'cat' and the command should be:

awk '{if((NR>122)&&(NR<128)) print}' test.log

Hope this will work for you (works for me )

If you want to use line numbers dynamically as variables, then use nawk instead awk:

nawk -v l1=$L1 -v l2=$L2 '{if((NR>l1)&&(NR<l2)) print}' test.log

Very helpful thank you!