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sed REGEX to print multiple occurrences of a pattern from a line

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# 1  
Old 08-20-2015
sed REGEX to print multiple occurrences of a pattern from a line
I have a line that I need to parse through and extract a pattern that occurs multiple times in it.

Example line:

Code:
getInfoCall: [ call=1 origin=AAAA ] info received please proceed, getInfoCall: [ call=3 origin=BBBB ] info received please proceed, getInfoCall: [ call=5 origin=CCCC ] info received please proceed, getInfoCall: [ call=2 origin=DDDD ] info received please proceed, getInfoCall: [ call=4 origin=EEEE ] info received please proceed

And I need to pull only the "call=1 origin=EEEE" patterns from this line. Like

Code:
call=1 origin=AAAA
call=2 origin=DDDD
call=3 origin=BBBB
call=4 origin=EEEE
call=5 origin=CCCC

I know we can do it with awk easily. But trying to know if there is a way we can try with SED regex.

Tried below and got only the last part of it.

Code:
echo "above string" | sed -e 's/.*\(call=[0-9]\) \(origin=[A-Z]\{4\}\).*/\1 \2/g'

call=4 origin=EEEE

Please help. Smilie
# 2  
Old 08-20-2015
Hello Vidyaprakash,

Following awk solution, may help you in same.
Code:
 awk '($0 == "call=4 origin=EEEE")'  Input_file


Thanks,
R. Singh
# 3  
Old 08-20-2015
Try
Code:
sed 's/^[^c]*\(call\)/\1/;s/ \(call\)/\n\1/g;s/\(origin=[^ ]*\)[^\n]*/\1/g' file
call=1 origin=AAAA
call=3 origin=BBBB
call=5 origin=CCCC
call=2 origin=DDDD
call=4 origin=EEEE

# 4  
Old 08-20-2015
Code:
sed 's#^[^[][^[]*\[##g;s#][^[]*##g' myFile | tr '[' '\n'

Last edited by vgersh99; 08-20-2015 at 02:36 PM..
# 5  
Old 08-20-2015
The following needs two lines
Code:
sed 's/[^[]*\[ *\([^]]*\) *\][^[]*/\1\
/g' file

GNU sed can take \n here
Code:
sed 's/[^[]*\[ *\([^]]*\) *\][^[]*/\1\n/g' file

Just realized, the [^]] include the trailing spaces; the following * does not delete them.
And how to get rid of the blank line?
Well, either remove the embedded \n at the end of the line buffer
Code:
sed 's/[^[]*\[ *\([^]]*\)\][^[]*/\1\
/g; s/\n$//' file

Or, move the newline before the match, and remove the first embedded \n
Code:
sed 's/[^[]*\[ *\([^]]*\)\][^[]*/\
\1/g; s/\n//' file

Last edited by MadeInGermany; 08-20-2015 at 03:39 PM..
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