Pass variable to awk command search string


 
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# 1  
Old 03-02-2015
Pass variable to awk command search string

I must have forgot how to do this, but, I am attempting to enter a variable into an awk / gawk search pattern.

I am getting a value from user input to place in a specific section of a 132 character string.

my default command is ....
Code:
gawk --re-interval '/^([ST].{3}P .{4}CYA.{8}1)/'  ${Arch_Dir}/${CYCLE}/${SUB_NAME} | wc -l

The above command does return information as expected, but ... the

"CY" characters are the two I want to substitute based on user input.

Code:
gawk -v val="$VAL" --re-interval .....

I have attempted to pass in my value via "-v", but I must have the syntax wrong.

Any help would be greatly appreciated!

Stu

Last edited by Scott; 03-02-2015 at 07:34 PM.. Reason: Code tags
# 2  
Old 03-02-2015
what is this suppose to do...'/^([ST].{3}P .{4}CYA.{8}1)/', I see a match but then what?

Last edited by Scrutinizer; 03-03-2015 at 02:17 AM..
# 3  
Old 03-02-2015
Can you close and reopen the awk around the variable?

Code:
gawk --re-interval '/^([ST].{3}P .{4}'$VAL'A.{8}1)/'  ${Arch_Dir}/${CYCLE}/${SUB_NAME} | wc -l

# 4  
Old 03-03-2015
Scott,

Thanks for helping me remember ! I am now able to evaluate each row of a file using different patterns with a specific input value placed anywhere in that 132 character string.

Stu
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