UNIX for Advanced & Expert Users

can any one help
i have a file with this content file name hsnvalue.op
containing
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
i want to print only one value to another file final.out

I couldnt understand your question properly.
Which value do you want to print ?

Print just one line to final.op

Code:

head -1 hsnvalue.op >> final.out

Print HSN and its value

Code:

echo "HSN=0,tool=123" | awk -F"," '{ print $1 }' >> /tmp/final.op

Print tool and its value

Code:

echo "HSN=0,tool=123" | awk -F"," '{ print $2 }' >> /tmp/final.op

file hsnvalue.op gets output as
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
HSN=0,tool=123
i want to move only one value to another file final.op since all lines are identical how do i get one value,remember the numerical value change every time u run next if u run net tin it give op to hsnvalue.op as
HSN=4,tool=566
HSN=4,tool=566
HSN=4,tool=566
HSN=4,tool=566
HSN=4,tool=566
HSN=4,tool=566

Did you go through the possible solutions I put up ?

If you did, you would have found that the first one would be upto your expectations.

ya it worked but if i have input file as
HSN=1,total=09
HSN=2,total=09
HSN=3,total=09
HSN=4,total=09
HSN=5,total=09
and want
HSN=2,total=09
HSN=3,total=09
HSN=4,total=09
only to move in another file

Here's another thought. It seems that you want to pick out unique lines from your list. Why dont you use uniq ? See man uniq.