Read file and skip the line starting with #


 
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# 15  
Old 03-31-2013
Quote:
Originally Posted by alister
No, you did not. Your original attempt is not the same.

What you did:
Code:
grep -v '^#' | while read line; do ... done < server.cfg

What rangarasan suggested:
Code:
grep -v '^#' server.cfg | while read line; do ... done

There is a big difference. Pipe redirections occur before other redirection operations.

rangarasan is telling grep to read the file. Your original solution has grep reading something else (whatever standard input descriptor it inherited, which could be a teriminal or some other file).

You redirected the file directly to the while-read loop, bypassing grep. Your grep is doing nothing. Even if there is something for it to read on standard input (we can't tell from your script what stdin is, since it depends on how the script is called), there is nowhere for the grep data to go. Why? Because after the pipe connects the standard output of grep to the standard input of the while-read loop, the standard input of the while-read loop is overridden by the redirection operation immediately following the while-loop. So, even if grep does write to the pipe, there is nothing on the other end to read the data.

On a different note, there is no need for grep. Within the while-loop, a case statement can do the job:
Code:
case $line in
    \#*) continue ;;
esac

Or, if the shell supports substring parameter expansion:
Code:
[ "${line:0:1}" = '#' ] && continue

Regards,
Alister
Hi,

hmm.. I think u guys misunderstanding..
I'm trying not only that way on my post..
I post before I search for solution..
and my post is the latest tried. so I decide to post that as my problem..
thanks for your solution..Alister.
I also did tried that, but still didn't work for me..
It prompt "bad substitution" in my error message. Smilie
# 16  
Old 04-11-2013
Hi all,

I have another problem..
I do some changes on my code

My code is something like this..
Code:
#!/usr/bin/sh
file2copy=$1
foldername=$2 
grep -v '^#' servers.cfg > valid_servers
while read line
 do 
  echo $line
  if ssh $line "if [ ! -d $foldername ]; then mkdir $foldername; fi"
  then echo " folder exists"
  else echo " error"
  fi
 
  if scp -r $file2copy $line:~/$foldername 
  then echo "File/Folder $file2copy fully copied ..."
  else echo "Error: $file2copy not copied ..."
  fi
done < valid_servers
exit

For example, valid_servers has 8 servers inside..
when I run the script, it only pass 4 servers.
But
if I "#" the ssh part, and let it run only the scp part (assume folder exist in all servers),
it doesn't have any problem, and successful to copy files into all the 8 servers.


Anyone know what happen in this problem? Smilie


FYI, I had keep trying the egrep command too..
maybe the space_bar or what make the script won't run,
and now it works with egrep too..
thanks Alister and Ranga. Smilie


Regards,
beezy Smilie
# 17  
Old 04-11-2013
ssh's standard input is the same descriptor that the while loop is reading. ssh is probably consuming some of the data. Try -n or explicitly overriding its stdin with /dev/null.

Regards,
Alister
# 18  
Old 04-11-2013
Quote:
Originally Posted by alister
ssh's standard input is the same descriptor that the while loop is reading. ssh is probably consuming some of the data. Try -n or explicitly overriding its stdin with /dev/null.

Regards,
Alister
Hi Alister,
thanks for your reply. You mean ssh -n $line..... ?


Thanks .. It works now. Smilie

Last edited by beezy; 04-11-2013 at 02:43 AM..
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