UNIX for Advanced & Expert Users

pprr0103 (01 as date and 03 as month)
pprr0203
pprr0603
...
...
pprr3103
pprr0304

Missing files as
pprr0303
pprr0403
pprr0503
pprr0104
pprr0204

for i in {01..31} #don't know how to work with calender dates. you can do it manually.. 
do
if [[ "$i" -lt "10" ]]
then
file="pprr0"$i"03" # Month - Change as 04, 05 and so on.
ls $file >/dev/null
    if [[ $? != 0 ]]
    then
    echo "$file is missing"
    fi
else

file="pprr"$i"03"
ls $file >/dev/null
    if [[ $? != 0 ]]
    then
    echo "$file is missing"
    fi
fi
done

ls  p*|sort -n -k1.7,1.8 -k1.5,1.6|
awk     'BEGIN {split("31 28 31 30 31 30 31 31 30 31 30 31", mdays)}

         function prtmiss (ld, ad, am) {for (i = ld+1; i < ad; i++) printf "pprr%02d%02d is missing\n", i, am}

        {day=substr($0,5,2)+0; mth=substr($0,7,2)+0;
         if (mth > prevm) {prtmiss(prevd, mdays[prevm]+1, prevm); prevd=0}
         prtmiss (prevd, day, mth);
         prevd=day; prevm=mth
        }'