UNIX for Advanced & Expert Users

Hello All,

I have following line and text file

line =08 * * 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g

file:- abc.crontab
08 * * 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g
06 * * 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g

I have searched the line using following command

grep -F "08 * * 3" abc.crontab | grep "abc.sql"

I get the first line from file,I want to delete the exact matching line from abc.crontab

If I use sed -e '/abc.sql /d' abc.crontab then both the lines get deleted from file. Please suggest me the solution.

Code:

 
$ line='08 \* \* 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g'
 
$ echo $line
08 \* \* 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g
$ grep -v "$line"  test.txt
06 * * 3 /data/reports/bin/xyz.ksh -o customreports.com -f abc.sql -m xyz.com -c -g

Line variable does not contain specific line ,Line may contain number of special character that will be unknown because line variable takes line at run time.So we cant guarantee about the specific special characters.
Is there any way to ?

Why don't you put the line value in a file (say, fpatt) and use

Code:

grep -Fvf fpatt inputfile