UNIX for Advanced & Expert Users

Hi,
I have a folder structure as follows,

Code:

DATA -> 2012-01-01 -> 00 -> ABC_2012-01-03_00.txt
                   -> 01 -> ABC_2012-01-03_01.txt
                   -> 02 -> ABC_2012-01-03_02.txt
                   ...
                   -> 23 -> ABC_2012-01-03_02.txt
     -> 2012-01-02
     -> 2012-01-03
     ....

So the dir DATA contains the above hierarchy,
User input Start and End Data
I want to grep on all those files between the input dates, I want a list of files which come under the input dates.
note that the files creation or modified date is not the date and hour contained in the file name so cannot use find newer/modified command.
So what could be the easiest way of doing it, After finding the files i want to grep a string "PQRS" on the selected files for the input dates.
Any help on this would be highly appreciated...!!! TIA

Moderator's Comments:

Duplicate thread: Continues here: https://www.unix.com/shell-programmin...file-name.html

Hi,
Try this one,

Code:

cd DATA
find . -name "*' | awk '/^\.\/2012-01-0[1-9]/{print;}'|xargs -I '{}' grep -l 'PQRS' {}

here i am listing all the files from jan 01-09 and then grepping for pattern, if found just displays the file name..
Cheers,
Ranga:-)