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Advance conditional grep command

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# 1  
Old 09-11-2011
Advance conditional grep command
Hi guys, I need your help to use advance grep command, In my example below, I have 5 container which has some information on it, and I need to grep specific word "PLMNCode=454F00" which will not only grep the line contains that word, but I need to print the output for the whole container.

Input file:

StartOfRecord
dateAndTimeStart = 20110904091315
PLMNCode=455F00
dateAndTimeEnd = 20110904091415
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110904091315
[COLOR="rgb(255, 0, 255)"]PLMNCode=454F00[/COLOR]
dateAndTimeEnd = 20110904091415
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110905142111
[COLOR="rgb(255, 0, 255)"]PLMNCode=455F00[/COLOR]
dateAndTimeEnd = 20110905152111
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110911122110
[COLOR="rgb(255, 0, 255)"]PLMNCode=454F00[/COLOR]
dateAndTimeEnd = 20110911122203
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110911122110
[COLOR="rgb(255, 0, 255)"]PLMNCode=460F00[/COLOR]
dateAndTimeEnd = 20110911122203
EndOfRecord


Example when I grep "PLMNCode=455F00" it should print out like (below), there are 2 container that contains the "PLMNCode=455F00".

StartOfRecord
dateAndTimeStart = 20110904091315
PLMNCode=455F00
dateAndTimeEnd = 20110904091415
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110905142111
[COLOR="rgb(255, 0, 255)"]PLMNCode=455F00[/COLOR]
dateAndTimeEnd = 20110905152111
EndOfRecord


Then finally, it will write on a outfile txt file.

Thank you in advance for your help guys!! This will really help me alot!
# 2  
Old 09-11-2011
If you have GNU grep, then try this
Code:
$ grep -A2 -B2 "PLMNCode=455F00" contents 
StartOfRecord
dateAndTimeStart = 20110904091315
PLMNCode=455F00
dateAndTimeEnd = 20110904091415
EndOfRecord
--
StartOfRecord
dateAndTimeStart = 20110905142111
[COLOR="rgb(255, 0, 255)"]PLMNCode=455F00[/COLOR]
dateAndTimeEnd = 20110905152111
EndOfRecord

---------- Post updated at 08:55 AM ---------- Previous update was at 08:54 AM ----------

Code:
$ grep --version
GNU grep 2.5.4

# 3  
Old 09-11-2011
Thanks for your response! I forgot to mention that there is no line space (as below), will it also work with GNU grep? Thanks again.

StartOfRecord
dateAndTimeStart = 20110904091315
PLMNCode=455F00
dateAndTimeEnd = 20110904091415
EndOfRecord
StartOfRecord
dateAndTimeStart = 20110904091315
[COLOR="rgb(255, 0, 255)"]PLMNCode=454F00[/COLOR]
dateAndTimeEnd = 20110904091415
EndOfRecord
StartOfRecord
dateAndTimeStart = 20110905142111
[COLOR="rgb(255, 0, 255)"]PLMNCode=455F00[/COLOR]
dateAndTimeEnd = 20110905152111
EndOfRecord
StartOfRecord
dateAndTimeStart = 20110911122110
[COLOR="rgb(255, 0, 255)"]PLMNCode=454F00[/COLOR]
dateAndTimeEnd = 20110911122203
EndOfRecord
StartOfRecord
dateAndTimeStart = 20110911122110
[COLOR="rgb(255, 0, 255)"]PLMNCode=460F00[/COLOR]
dateAndTimeEnd = 20110911122203
EndOfRecord
# 4  
Old 09-11-2011
yes, it will
# 5  
Old 09-11-2011
Hi Itkamaraj,

This works like a charm! Just one more question, because if the number of line is not fixed, the example I provided above contains 5 lines per container, what if it occured more than five lines? Is it possible to treat the "StartOfRecord" and starting point then "EndOfRecord" end point?
# 6  
Old 09-11-2011
In that case, it works for you.
Code:
$ awk 'BEGIN{RS="EndOfRecord"} $0~/PLMNCode=455F00/ {print $0"EndOfRecord"}' contents.bk 
StartOfRecord
dateAndTimeStart = 20110904091315
PLMNCode=455F00
dateAndTimeEnd = 20110904091415
EndOfRecord

StartOfRecord
dateAndTimeStart = 20110905142111
[COLOR="rgb(255, 0, 255)"]PLMNCode=455F00[/COLOR]
dateAndTimeEnd = 20110905152111
EndOfRecord

# 7  
Old 09-11-2011
Hi itkamaraj,

Works great! thanks alot for your help, this really saved hours of my work load. Smilie
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