UNIX for Advanced & Expert Users

Hi all
Thanks in advance...........

Please help me for this issue............

I have a file it has 11 records . I used the command like ....

Code:

>$ wc -l file
11 file

I'm getting output like 11 file (no.of records along with filename)

here my requirement is, I want to display only no.of records without filename
like only 11.

can anyone please tell me which command I have to use?

because if I get this no.of records I have to comapre with some outfile
so shall I assign this no.of records to any variable ?

Thanks
Srivani Kolachina

try this

Code:

 
wc -l < file

otherwise, use awk, cut,...etc...

---------- Post updated at 12:44 PM ---------- Previous update was at 12:31 PM ----------

Code:

 
grep -c . file

---------- Post updated at 12:44 PM ---------- Previous update was at 12:44 PM ----------

Code:

 
awk '{i++;} END{print i}' file

---------- Post updated at 12:46 PM ---------- Previous update was at 12:44 PM ----------

Code:

 
perl -lane '$i++;END{print $i}'  file

Thanks a lot ....

>$ wc -l < file
11

But I want to assgin this output to any variable?

I'm declaring like below.

Code:

j=wc -l < file
k=wc -l <outfile
 
if [ $j -eq $k ]
then 
  echo " both are same "
else
  echo " not same"
fi

my program is like this ... but it is giving error like

Code:

ex: line 13: -l: command not found
+ k=wc
+ -l
ex: line 14: -l: command not found

but giving the output properly...
can u please tell me y it is giving like this?

Thanks
Srivani

Code:

j=`wc -l < file`
k=`wc -l <outfile`

use back ticks

or use it like below

Code:

 
j=$(wc -l < file)