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can you explain this AWK "c+" statement ?

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Top Forums UNIX for Advanced & Expert Users can you explain this AWK "c+" statement ?
# 1  
Old 10-01-2004
can you explain this AWK "c+" statement ?
Well i use the following statement in a script to calculate the all column value of a ls command :

find . -name *.leon -exec ls -al {} \;|awk '{c+=$5} END {print c}'

And this is the result :
2.34546e+09

i would know what is exactly the "c+" role , and what i must modify to have the result in bytes :
2345460000

thanks in advance

christian
# 2  
Old 10-01-2004
The "c+=$5" means that for each record, the value of the fifth field should be added to whatever the value of c already is - i.e., it has the effect of summing all values in the fifth field of the data.

This is equivalent to saying

c = c + $5

Cheers
ZB
# 3  
Old 10-01-2004
Sorry, just saw your second question.

Change the awk to have this at the end
END {printf "%d\n", c}'

Cheers
ZB
# 4  
Old 10-01-2004
running this :

find . -name *.nsf -exec ls -al {} \;|awk '{c+=$5} END {printf "%d\n", c}'

i got :

find: missing conjunction
0

some mistake ??? and what 's the difference ?

thanks

christian
# 5  
Old 10-02-2004
Strange.... that command works fine under my system (Linux).

Try including a -print (even though it shouldn't be necessary)

find . -name *.nsf -print -exec ls -al {} \;|awk '{c+=$5} END {printf "%d\n", c}'

Cheers
ZB
# 6  
Old 10-04-2004
Well i don't know why , this works if i put "*.nsf" in place of *.nsf
maybe this is related to the number of files concerned ??

christian
# 7  
Old 10-04-2004
I (or somebody else) should have noticed that....

All globbing (i.e. wildcard matches) within finds must be "quoted", e.g. "*.thisworks" but *.thisdoesnt.

Cheers
ZB
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