UNIX for Advanced & Expert Users

Hi
I have a program test.ksh

#! /bin/ksh
echo $1
echo $2

when i run this from command line like ksh test.ksh abc def
Its echoing the passed arguments correctly where as if i run form commadn line like test.ksh abc def its not echoing the parameters saying like test.ksh not found.But i ma running this in the command line on the directlry where the program residese . I gave echo $SHELL in command its resolving to /usr/bin/ksh also echo $PATH is resolvng to /usr/bin.

I just want to know why the option2 is not working

Your help is apprecaited.

Your problem is nothing to do with the script itself, it's that the script is not being found in your PATH, most likely either because you forgot to mark the script as executable, or because your PATH does not include the current directory. Try this:

chmod +x test.ksh
./test.ksh abc def

and it ought to work.

Hi Phil

Thanks for you reply,sorry i didn't mention in my provious thread.

Already it has given the permissions as 777 and also i tried earlier with ./test.ksh its working fine.

Since my programs will be called from the mainframe scheduler,in mainfrmae control card they can't give ./test.ksh they have given like test.ksh and also its very hard now to go and chnge in mainfrmaes.

I have pasted the the way i executed please see below.

PROD ca7dss@a1pvdb071 /dss/run > ls -ltr *test.ksh*
-rwxrwxrwx 1 ca7dss dss 66 Aug 21 20:49 test.ksh
PROD ca7dss@a1pvdb071 /dss/run > test.ksh abc def

No of argumetns passed is : 0
ksh[4]: test.ksh: not found.
PROD ca7dss@a1pvdb071 /dss/run > more test.ksh
#! /bin/ksh
echo $1
echo $2
echo "No of argumetns passed is : $#"

Kindly help me on this.

Then you need to either put that script in a directory somewhere in the default system path, or find a way to have the caller specify the full path to it.

Hi Phil

Thanks,

I just added the path where i am running this program in to $PATH.

Now its working fine.

Thanks a lot.