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Retrieving accurate file timestamp

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# 1  
Old 04-30-2009
Retrieving accurate file timestamp
Hi Gurus,

The requirement is to collect the timestamp of soft links and collect it in a file in the following pattern:

This is the expected output:

Pattern:
MM/DD/YYYY hh:mi:ss filename

Example:
12/26/2008 10:31:09 <Filename>.zip

The closest way I could get was this:
Code:
ls -lrt | awk -F" " '{print $6"-" $7" ", $8" ", $9}'  > $AUDIT_FILE

But, the output was:

Pattern:
MMM-DD HH:mi filename
Sample:
Apr-29 18:45 <FileName>.zip

Can I get the seconds and the year when the file was changed.

Thanks,
Jiddvish.
# 2  
Old 04-30-2009
Are you using Linux? If so check out the stat command.
# 3  
Old 04-30-2009
I am on Solaris and programming through ksh.

Code:
uname -a
SunOS <ServerName> 5.9 Generic_118558-35 sun4u sparc SUNW,Sun-Fire-V490

# 4  
Old 04-30-2009
this could be done with a small perl script or one liner using stat() and localtime().

check this out. https://www.unix.com/tips-tutorials/2...ime-atime.html

There are may other examples on the forum you can search for.
# 5  
Old 05-01-2009
Hi Frank,
Thanks for the solution, works superbly for me, but I have another issue. The files whose timestamps are being collected are soft links and the timestamps that are getting generated are of the actual file. I need to collect the timestamp of the link file that is getting created.

Code:
for LINKS in `ls`
do
    TIMESTAMP=`perl -e '@d=localtime ((stat(shift))[8]); printf "%02d/%02d/%4d %02d:%02d:%02d\n", $d[4]+1,$d[3],$d[5]+190
0,$d[2],$d[1],$d[0]' $LINKS`
     echo $TIMESTAMP $LINKS
done

Also, is there any way I can pass the filenames directly in a single command without using the for loop. I tried

Code:
find ./ -type f <perl command> {} \;

but it does not work.

any help here is really great.
# 6  
Old 05-01-2009
Code:
ls -l --time-style=full-iso | awk '{print $6,substr($7,1,8),$9}'

cheers,
Devaraj Takhellambam
# 7  
Old 05-01-2009
Quote:
Originally Posted by jidsh
Hi Frank,
Thanks for the solution, works superbly for me, but I have another issue. The files whose timestamps are being collected are soft links and the timestamps that are getting generated are of the actual file. I need to collect the timestamp of the link file that is getting created.

Code:
for LINKS in `ls`
do
    TIMESTAMP=`perl -e '@d=localtime ((stat(shift))[8]); printf "%02d/%02d/%4d %02d:%02d:%02d\n", $d[4]+1,$d[3],$d[5]+190
0,$d[2],$d[1],$d[0]' $LINKS`
     echo $TIMESTAMP $LINKS
done

Also, is there any way I can pass the filenames directly in a single command without using the for loop. I tried

Code:
find ./ -type f <perl command> {} \;

but it does not work.

any help here is really great.
Code:
find ./ -type f -print -exec command '{}' \;


cheers,
Devaraj Takhellambam
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