Appending file extensions to filenames in bash scripts


 
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Special Forums UNIX Desktop Questions & Answers Appending file extensions to filenames in bash scripts
# 8  
Old 05-18-2010
Okay it's quite long so here goes:

I have files stored in different directories, hence I have put directory names into variables:

Code:
dsxfile="$dsxfile"
csvfile="$csvfile"
filename=""
cfile=""
csvdir="/var/local/dsx/csv"
dsxdir="/var/local/dsx/import"

Here is my scriptname that is called like so from the command line:
Code:
./Import_PlannedBSC.sh -b

I have getops that when I call the script with the -b option, it calls a function batchConverter which is the most important part here
Code:
while getopts " c: d: b h " option
do
	case $option in
		c ) csvfile="$OPTARG";;
		d ) dsxfile="$OPTARG";;
		b ) batchConverter;exit;;
		h | ? | * ) displayHelp;exit;;
		
	esac;
done

Here is my function which pulls all files that have filename "_bsc_" pattern and then removes it's file extension called .csv and then appends a new file extension called .dsx



Code:
function batchConverter
{
	for cfile in $csvdir/*_bsc_*;
	do
		filename=${cfile%%.*} 
		 mv $cfile $filename.dsx  
		echo ${filename##*/} 
  	      
	done
}

I want the filename without the path. The I copy these new files to another directory called $dsxdir
# 9  
Old 05-18-2010
Code:
filename=${cfile%%.*}.dsx
mv $cfile $dsxdir/${filename##*/}

This User Gave Thanks to Scott For This Post:
# 10  
Old 05-18-2010
At what point do I add the new file extension?
# 11  
Old 05-18-2010
You can do
Code:
filename=${cfile%%.*}.dsx
mv $cfile $dsxdir/${filename##*/}

Or
Code:
filename=${cfile%%.*}
mv $cfile $dsxdir/${filename##*/}.dsx

It really makes no difference...
# 12  
Old 05-18-2010
Thank you, the second option works brilliantly. Problem is that both the files are moved to the $dsxdir directory, but it's no problem, I will try and sort that out.
Thank you so so so much for all your help
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