7 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi Experts,
I created a powershell script to fetch user details from active directory and export it to a csv/excel.
"abc","bcd","devloper;admin"
"bcd","dca","tester;QA;admin"
So here user abc is member of devloper and admin group and user bcd is a member of tester,QA and admin... (6 Replies)
Discussion started by: shekhar_4_u
6 Replies
2. Shell Programming and Scripting
how to replace the 10th colum? Each line begins similarly, but they all ends variously.
Col1,Col2,Col3,Col4,Col5,Col6,Col7,Col8,Col9,Col10,Col11,Col12,Col13,Col14,Col15,Col16,Col17
2015/03/14 15:00:04,2015/03/14 15:00:04,0,Server05,Omega-God,Beta_G,101011247,1,1,24,7,0,,339083645,1,1,... (9 Replies)
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3. Shell Programming and Scripting
All,
I am attempting to print the tenth ($COPY2) varaibales into one file.
But i am finding that all variables are being outputted except for $10.
Can someone help!!!!
Code Below
----------
echo $SERVER $IMAGE $IMAGEDAY $IMAGEMONTH $IMAGEYEAR $COPY1 $EXPIREDAY $EXPIREMONTH... (1 Reply)
Discussion started by: Junes
1 Replies
4. Shell Programming and Scripting
I have a file that I do a count on :
cp $file data1
x=$(grep -c "Considerations:" data1)and I need to cut the file after the 10th occurrence of the word 'Considerations:' in $file (1 Reply)
Discussion started by: dba_frog
1 Replies
5. Shell Programming and Scripting
Hi,
I need to search for a word in a file and need to extract exactly 10th line before and after that search string.
Awaiting your earlier updates. Thanks in advance. (8 Replies)
Discussion started by: Sekar1
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6. Shell Programming and Scripting
Hi,
I would like to list latest 2 days, 3 days or 4 days,etc of files in the directory...
how? is it using ls? (3 Replies)
Discussion started by: happyv
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7. Shell Programming and Scripting
Hello,
I need some help ....i have a file with many number of fields i want to replace the 10th field of the file by number 2 .Also the delimeter of the file is | .
Pls suggest and help..
Regards, (2 Replies)
Discussion started by: PradeepRed
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CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD
June 6, 1993 BSD
