sqlite: calculating with dates - compare current date minus 6 months with stored record


 
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Old 03-10-2011
sqlite: calculating with dates - compare current date minus 6 months with stored record

Hi

I have a table with name, date in format DD.MM.YYYY.

Quote:
name expiry date
example CA 04.05.2013
example Sub-CA 01.09.2012
I need to something like this (I try to explain in pseudo code)

Code:
if SYSDATE (current date) minus 6 months > $expiry date
print OK
else print NOK with $name and $expiry date

I know this is possible with Oracle. How to do this in sqlite?
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PX_DATE2STRING(3)														 PX_DATE2STRING(3)

px_date2string - Converts a date into a string.

SYNOPSIS
string px_date2string (resource $pxdoc, int $value, string $format) DESCRIPTION
Turns a date as it stored in the paradox file into human readable format. Paradox dates are the number of days since 1.1.0000. This func- tion is just for convenience. It can be easily replaced by some math and the calendar functions as demonstrated in the example below. PARAMETERS
o $pxdoc - Resource identifier of the paradox database as returned by px_new(3). o $value - Value as stored in paradox database field of type PX_FIELD_DATE. o $format - String format similar to the format used by date(3). The placeholders support by this function is a subset of those supported by date(3) (Y, y, m, n, d, j, L). RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 Turn a paradox date into a human readable form <?php $px = px_new(); /* make up a date as it could be stored in */ /* a date field of a paradox db. */ /* 700000 days since 1.1.0000. */ $days = 700000; /* Use the calendar functions to print a */ /* human readable format of the date */ echo jdtogregorian($days+1721425)." "; /* px_date2string() outputs the same */ echo px_date2string($px, $days, "n/d/Y")." "; px_delete($px); ?> The above example will output: 7/15/1917 7/15/1917 SEE ALSO
px_timestamp2string(3), jdtogregorian(3). PHP Documentation Group PX_DATE2STRING(3)