Solaris

Hi,

Can anyone suggest a Unix command or c-shell algorithm to simulate to behavior of "wall" command minus the "all users"? What I'm trying to do is to send a notice to just one particular user but i dont want other remotely-logged-on users to receive the message (on the pseudo-terminals). I cannot use the "write" command for three reasons:
1. I (sender) will not be typing the message from standard input (instead, i will be using a file input)
2. I (sender) is not logged in to the same host as the receiver.
3. I want the message to appear on all terminals of the intended receiver.

Thanks in advance for your ideas...

ok... as root, i will send a message to the user "pressy" on all of his terminals...

Code:

root@mp-wst01 # who
pressy     pts/1        May 11 09:51    (pressynb.ips.local)
pressy     pts/2        May 11 09:51    (pressynb.ips.local)
root       pts/3        May 11 09:51    (pressynb.ips.local)
root@mp-wst01 # who | awk '$1~/pressy/ {print $2}' | while read PTS; do print "\nALERT!\n" > /dev/$PTS; done
root@mp-wst01 #

regards pressy

pressy what shell are you using? I get a while expression syntax and undefined variable pts.

also, im afraid your code requires me to be logged in to the same host as the receiver.....

i am working in the korn shell (standard /usr/bin/ksh, Version M-11/16/88i), seems that you are using CSH... no clue how it works there....

well, you could create a script for that, save it somewhere and execute it from remote, for example with ssh root@mp-wst01 -C "/root/message.sh". but yes, for the message itself you will need to execute a command on the remote host...
to find a remote logged in user, i could think about finger:

Code:

root@jumpy # finger pressy@mp-wst01
[mp-wst01]
Login       Name               TTY         Idle    When    Where
pressy          ???            pts/2          8 Fri 17:20  pressynb.ips.local
root@jumpy #

but to send him a message directly, hmm, good question... any ideas mates?

regards PRESSY