Solaris

Guys,

I am trying to use this command to find out the occurrence of the service "Loadservice" from the log file "log.06102010.svr1" in between the time frame 02:00:00 to 03:00:00 on the day 06-10-2010.

Code:

sed -n '/2010-06-10 02:00:00/,/2010-06-10 03:00:00/p' | fgrep "Loadservice" log.06102013.svr1 | wc -w

I just need to find the wordcount of Loadservice and I am getting incorrect outcome from the above command. Any help will be really appreciated.

Regards,
Kris

sed doesn't work that way. If you don't have a line EXACTLY matching 2010-06-10 02:00:00, it will never begin, and if you don't have a line EXACTLY matching 2010-06-10 03:00:00 it will never end.

Also, word count probably isn't what you're looking for, but the number of lines containing that word.

You can probably do it with awk, but we will need to see what your logfile looks like.

I need the number of words of 'Loadservice' between 2-3 AM

Show a line with 'loadservice' in it and how you expect it to be counted.

The first command in your pipe should open the file; the second command should default to its stdin (that reads from the pipe).
But perhaps can be boiled down to one sed command

Code:

sed -n '/2010-06-10 02:/,/2010-06-10 03:/{/Loadservice/p;}' log.06102013.svr1

Still it needs to find at least one 02: and one 03: entry in the file.
It is identical with

Code:

sed '/2010-06-10 02:/,/2010-06-10 03:/!d;/Loadservice/!d' log.06102013.svr1

Thanks MadeinGermany.

Tats works perfectly fine and if you add grep Loadservice | wc -l at the end it gives me the perfect count.

sed '/2010-06-10 02:/,/2010-06-10 03:/!d;/Loadservice/!d' log.06102013.svr1 |grep Loadservice | wc -l

---------- Post updated at 09:28 AM ---------- Previous update was at 09:26 AM ----------

I need the count for every hour, so I am trying to put this in a script which gives me the output for every single hour from 00:00 to 23:00

Please show a line with 'loadservice' in it and how you expect it to be counted.