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Operating Systems Solaris Processing user input in .sh file
# 1  
Old 09-27-2010
Processing user input in .sh file
Hi,

I am new to shell scripting.

script should accept the user value and then compare that value with the null.

If null then assign the value "*" to the variable else will use the user inputed value.

How to do this ?

With Regards
# 2  
Old 09-27-2010
Code:
#!/bin/ksh
invalue="$1"
if [[ "$invalue" = "" ]]
then
 invalue="*"
 print "$invalue"
 else
 print "$invalue"
fi

Usage:
Code:
 
./a.sh hi
hi
 
./a.sh
*

# 3  
Old 09-27-2010
Hi,

The thing is I want to schedule the cron job using shell scripting
So, if the user dont input the value then script will accept as "*"
I have done something as shown below but not getting desired output.

Code:
#-----------------------------
# Set the values for cron job
#-----------------------------

printf "$FBOLD\nPlease enter the minute (0-59):  $FREG"
read minute
    if [ "$minute" = "" ] 
    then
     minute="*"
     printf "$minute"
     else
     printf "$minute"
    fi

With Regards
Last edited by pludi; 09-27-2010 at 08:45 AM.. Reason: code tags, please...
# 4  
Old 09-27-2010
Code:
 
#!/bin/bash
read -p "Please enter the minute (0-59):" minute
if [ "$minute" = "" ] 
then
minute="*"
echo "$minute"
else
echo "$minute"
fi

This User Gave Thanks to malikshahid85 For This Post:
milink
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