10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello,
one step in a shell script i am writing, involves Grep command to search a regular expression in a line an only print the string after the match
an example line is below
/logs/GRAS/LGT/applogs/lgt-2016-08-24/2016-08-24.8.log.zip:2016-08-24 19:12:48,602 ERROR... (9 Replies)
Discussion started by: Ramneekgupta91
9 Replies
2. Shell Programming and Scripting
Use sed to print first n lines and last n lines of an output.
For example: n=10
Can it be done?
Thanks. (7 Replies)
Discussion started by: carloszhang
7 Replies
3. Shell Programming and Scripting
I am trying to extract a table of data (mysql query output) from a log file. I need to print everything below the header and not past the end of the table. I have spent many hours searching with little progress. I am matching the regexp +-\{99\} with no problem. I just can't figure out how to print... (5 Replies)
Discussion started by: godfreydanials
5 Replies
4. Shell Programming and Scripting
Hello All,
I have something like below
LDC100/rel/prod/libinactrl.a
LAA2000/rel/prod/libinactrl.a
I want to remove till first forward slash that is outputshould be as below
rel/prod/libinactrl.a
rel/prod/libinactrl.a
How can I do that ??? (8 Replies)
Discussion started by: anand.shah
8 Replies
5. Shell Programming and Scripting
I would like to print 3 lines after a regular expression is found in the logfile. I'm using the following code:
grep -n "$reg_exp" file.txt |while read LINE ;do i=$(echo $LINE |cut -d':' -f1 ) ;sed -n "$i,$(($i+3))p" file.txt ;done
The above code things works fine,but sometimes gives erroneous... (3 Replies)
Discussion started by: joachimshaun
3 Replies
6. Shell Programming and Scripting
I have read many threads, but I still didn't find the right answer. May be i didn't find the right thread, though are so many threads for the same question.
Basically the situation is - find date in a file and replace it with another date. (its not homework, its part of lot of a big processing,... (10 Replies)
Discussion started by: avinthm
10 Replies
7. Shell Programming and Scripting
I am trying to print those line which has no # in the begining of the line.
The sed I used for this purpose as shown below is not giving the required output.
echo 'PDE 5600' | sed -n 's/^\!#/&/p'
Where lies the problem:confused: (3 Replies)
Discussion started by: hiten.r.chauhan
3 Replies
8. Shell Programming and Scripting
Hey, I found a way to print the lines which is just before a regular expression, not including the expression.
sed -n '/regexp/{n;p;}' myfile
Now I'm looking for a way to print all lines, exept the regular expression and also the line before the same regular expression.
Use code tags. (1 Reply)
Discussion started by: Livio
1 Replies
9. Shell Programming and Scripting
Hi,
I have a file like this
comment.txt
1.img
2.img
3.img
OK
x.img
y.img
z.img
not ok
1.img
2.img
3.img
bad
1.img
2.img
3.img (7 Replies)
Discussion started by: avatar_007
7 Replies
10. Shell Programming and Scripting
Hi -
I am guessing this is fairly simple for someone .. but I can not quite figure it out. I need a sed command to print just parts of lines from a file.
e.g. filea.txt
4710451 : Success : MODIFY : cn=user1,dc=org,dc=uk
Message log started
Message log ended
4710452 : Success : MODIFY :... (7 Replies)
Discussion started by: sniper57
7 Replies