Solaris

Hello all,
I have 3 scripts that I have to run using cron tab and 2 scripts are dependent on the first script.

How do I schedule cron jobs such that 2nd job follows first and 3rd follows 2nd.

For example, I have 3 jobs - job1, job2 and job3, that have to run every 3 hours.

I want the jobs to run in the following order.
If job1 is successful, run job2
If job2 is successful, run job3.

Will this work?

Code:

0 0-23/3 * * * job1 && job2 && job3

A simpler solution is to create a wrapper script to check the return codes of each process. Run the wrapper script once every three hours.

The example you gave will work - but be sure to enter the full file specification:
/path/to/job1 && /another/path/job2

It won't because the 0-23/3 syntax is incorrect. The && stuff is right though.

Then how do we schedule to run the job every 3 hours everyday?

Please let me know!

This should work;

Code:

0 0,3,6,9,12,15,18,21 * * *

That depends. The Vixie Cron (written by Paul Vixie) on Linux systems does support an extension that uses the slash to indicate an interval.

You are right, while that syntax is incorrect in that Solaris forum context, I should have written it is unsupported.