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How to get next string of a matching string?

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# 1  
Old 10-23-2014
How to get next string of a matching string?
Code:
fruits="apple grape orange jack lemon"

I want the element present next to "orange". i.e. jack
Note: The position of orange is not fixed.

Code:
fruits="apple grape orange jack lemon"

echo $fruits | awk '{ for ( n=1; n<=NF; n++ ) if($n ~ my_string) print $n }' my_string="orange"

This will print "orange" but i want to print "jack"

Code:
 print {$n+1}

is throwing error

Im not restricted to awk. Any other approach is appreciated.
Thanks.
# 2  
Old 10-23-2014
Code:
fruits="apple grape orange jack lemon"
echo $fruits | awk '{ for ( n=1; n<=NF; n++ ) if($n == my_string) print $(n+1)  }' my_string="orange"
jack

---------- Post updated at 06:25 PM ---------- Previous update was at 06:19 PM ----------

OR like this

Code:
fruits="apple grape orange jack lemon"
echo $fruits | awk '$1==my_string{ n=FNR+1 }FNR==n' RS=" " my_string="orange"
jack

This User Gave Thanks to Akshay Hegde For This Post:
Arun_Linux
# 3  
Old 10-23-2014
With a recent ksh or bash, you could also try using arrays in the shell:
Code:
#!/bin/ksh
fruits=(apple "honeydew melon" grape orange jack lemon)
for i in "$@"
do	for (( f=0; f < ${#fruits[@]}; f++))
	do	if [ "${fruits[f]}" = "$i" ]
		then	printf 'Fruit after %s is %s\n' "$i" \
				"${fruits[(f + 1) % ${#fruits[@]}]}"
			break
		fi
	done
	if [ $f -ge ${#fruits[@]} ]
	then	printf 'Fruit %s not found\n' "$i"
	fi
done

which when invoked with the operands:
Code:
apple jack lemon pear

produces the output:
Code:
Fruit after apple is honeydew melon
Fruit after jack is lemon
Fruit after lemon is apple
Fruit pear not found

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