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awk script giving unstable results

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Top Forums Shell Programming and Scripting awk script giving unstable results
# 8  
Old 08-07-2009
Code:
psg ServTest | awk '! /vi|awk/ && $8 == "ServTest" { print "ServTest Present" }'

jean-Pierre.
# 9  
Old 08-11-2009
Quote:
Originally Posted by Anteus
Hi all

Here I came accross a situation which i am unable to reason out...

snippet 1
Code:
 
psg ServTest | grep -v "grep" | grep -v "vi" | awk '{
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Present =" cmd_name}
}'
Output is 
awk
ServTest not running! = ServTest
anteus 12576 12572  1 05:31:52 pts/t41   0:00 awk {
ServTest not running! = ServTest
    pgm_name=$8
ServTest not running! = ServTest
   cmd_name="ServTest"
ServTest not running! = ServTest
gsub(/[[:spa
ServTest Present =ServTest

snippet 2
Code:
psg ServTest  | grep -v "grep" | grep -v "vi" | awk '{
     print "Count"
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Running" }
}'
Output is
count
ServTest Running

even if we comment the line print "Count" .the code gives expected output.
snippet 3
Code:
 
psg ServTest  | grep -v "grep" | grep -v "vi" | awk '{
     #print "Count"
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Running" }
}'
Output is
ServTest Running

can any one tell me why is this behavior....??

Thanks and Regards
Why is code snippet 1 and 3 giving different output.?
Can anyone tell me this.

Thanks and Regards.
# 10  
Old 08-11-2009
Please show us the result of the psg command, add a debug print instruction in the awk scripts

snippet 1
Code:
psg ServTest | grep -v "grep" | grep -v "vi" | awk '1 {printf "debug -", $0 } {
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Present =" cmd_name}
}'

snippet 2:
Code:
psg ServTest  | grep -v "grep" | grep -v "vi" | awk '1 {printf "debug -", $0 } {
     print "Count"
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Running" }
}'

Jean-Pierre.
# 11  
Old 08-14-2009
snippet 1
Code:
psg ServTest | grep -v "grep" | grep -v "vi" | awk '1 {printf "debug -", $0 } {
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Present =" cmd_name}
}'

Result debug -ServTest Present =ServTest

snippet 2:
Code:
psg ServTest  | grep -v "grep" | grep -v "vi" | awk '1 {printf "debug -", $0 } {
     print "Count"
     pgm_name=$8
     cmd_name="ServTest"
     gsub(/[[:space:]]*/,"",pgm_name)
     if(pgm_name==cmd_name) { print "ServTest Running" }
}'

Result
debug -count
ServTest Running


-----
and this is my code and its output

Code:
psg ServTest| grep -v "grep" | grep -v "vi" | awk '{
print "count"
pgm_name=$8
cmd_name="ServTest"
gsub(/[[:space:]]*/,"",pgm_name)
if(pgm_name==cmd_name)
{
  print "ServTest Present =" cmd_name
}
}'

count
count
count
count
count
count
ServTest Present =ServTest

can u please explain me why is count being printed 6 time instead of one.
Last edited by Anteus; 08-14-2009 at 03:35 AM..
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