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Help for "if condition" - need your help

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Top Forums Shell Programming and Scripting Help for "if condition" - need your help
# 1  
Old 06-30-2018
Wrench Help for "if condition" - need your help
Hi Friends
Need you help on this.
i used below line in my script

Code:
#! /bin/bash
read var
if  [ "$var" != "0" ] || [ "$var" != "Q1000" ]
then
    echo "YES"
else
    echo "NO"
fi

i want conditoin not equal Q1000 - Q1999 in my script.
i try below.

Code:
#! /bin/bash
read var
if  [ "$var" != "0" ] || [ "$var" != "Q1???" ]
then
    echo "YES"
else
    echo "NO"
fi

and


Code:
#! /bin/bash
read var
if  [ "$var" != "0" ] || [ "$var" != "Q1[000-999]" ]
then
    echo "YES"
else
    echo "NO"
fi

but not work.

Please help.

Thank
# 2  
Old 06-30-2018
Code:
 if [[ $var != "0" ]] && [[ ! $var =~ Q1[0-9][0-9][0-9] ]]

# 3  
Old 06-30-2018
Quote:
Originally Posted by Aia
Code:
 if [[ $var != "0" ]] && [[ ! $var =~ Q1[0-9][0-9][0-9] ]]

syntax error at source line 1
context is
{if( ! $var >>> =~ <<<


my os = sunos
# 4  
Old 06-30-2018
The example you got from aia did not have a parenthesis in it
Code:
# yours
if( ! $var >>> =~ <<< 
# note spaces are needed  on BOTH sides of any of these: [ ] [[ ]]
# because they are keywords bash like if or read
# should be:
if [ ! $var

# 5  
Old 06-30-2018
i try use awk + if

Code:
|awk -F"."  '{if( $2 != "Q1[0-9][0-9][0-9]" ) print $2}'  |sort |uniq -c |sort -k1nr |head -n6


can help me.
# 6  
Old 06-30-2018
awk is definitely not needed. Depending on your bash version, Aia's proposal (type in as presented!) should work satisfyingly.
If it doesn't, pls. post your bash versions, the script you tried to run, error messages verbatim, and an execution log (set -x option).
# 7  
Old 06-30-2018
Change to:
Code:
'{if( $2 ! ~  /Q1[0-9][0-9][0-9]/ )  print $2 }

the /pattern goes here/ thing delimits a regular expression pattern, which is what you are using. It works with the ~ character instead of the = character.

If you change anything else, please give more of your code to work with.
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