Shell Programming and Scripting

Are you sure your looking at "outa.txt" and not "outa1.txt" or "outa2.txt" from the previous version of the program?

Hi Chubler.

I ran the script after changing the names - to avoid the confusion. The result is the same, I see only the data extracted from out3.log. Thanks!

Any suggestions please.. Eager to try out you suggestions so that it takes care of my looong analysis. Thanks a lot

Try this and check your outa.log file then:

Code:

rm -f outa.txt
for i in out1 out2 out3; do 
   echo "===== Processing file $i =====" >> outa.txt
   awk '/ test-file*/{print;m=0}' $i.log >> outa.txt
   echo "===== Finished with file $i =====" >> outa.txt
   awk '/ test-string/{m=1;c=0}m&&++c==3{print $2 " " $3 " " $4}m&&c==13{print $2 " " $3 " " $4 ;m=0}' $i.log > ${i}c.txt
done

Thank you Chubler. The code worked great. I appreciate your time and help!!!
However, if I have to repeat the same for second awk (I have made a separate
script), it doesn't work.

rm -f outb.txt
for i in out1 out2 out3; do
echo "===== Processing file $i =====" >> outb.txt
awk '/ test-string/{m=1;c=0}m&&++c==3{print $2 " " $3 " " $4}m&&c==13{print $2 " " $3 " " $4 ;m=0}' $i.log >> outb.txt
echo "===== Finished with file $i =====" >> outb.txt
done

cat out*.log | awk ....