syntax problem grepping?


 
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# 8  
Old 07-17-2007
Dsimpg1,
We have done our best to explain it to you that the way you have it,
it does not work.

The reason is that your variable <GREPTIME2> has single quotes
surrounding it, thus the 'grep' is not doing what you want.

I suggest you make the recommended changes and test it.

You will realize that our solution works.

Last edited by Shell_Life; 07-17-2007 at 05:34 PM..
# 9  
Old 07-17-2007
Perhaps an example would better explain what is happening
Code:
$cat example
VAR="abc"
VAR1="' "$VAR"'"
VAR2=" $VAR"
echo "VAR1=$VAR1"
echo "VAR2=$VAR2"
echo "data for VAR1 abcdef" |grep "$VAR1" 
echo "data for VAR2 abcdef" |grep "$VAR2" 

$ksh example
VAR1=' abc'
VAR2= abc
data for VAR2 abcdef

Your grep is looking for a single quote, a space, the date, and another single quote. Your grep does not look for a space followed by the date.
# 10  
Old 07-17-2007
My apologies to all for not understanding what it is you were trying to say. Yes, you were correct, I was searching for it with quotes. Now that I have done what you said and removed the conversion to GREPTIME2 (I am only using GREPTIME now), it works as it should. Guess I tried to make something a little more complicated than it needed to be. Again, sorry. Thanks for all of your help!
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