Why when using realloc, john is reversed 3 times but not the other 2 names ? But if I use malloc, then the 3 names are reversed correctly ? (but then there is a memory leak)
How can I reverse all 3 names without a memory leak ?
The way you set up your code, you were sending const strings to the reverser.
You had to call something like strdup() - automagic way to duplicate strings - or malloc or realloc.
In that case: You need to have separate objects for each call to strrev. The objects have to be created in the calling routine not the strrev routine. This is because you called all three in one function call to printf().
You also could have used printf() free() printf() free().. using your malloc code.
---------- Post updated at 20:45 ---------- Previous update was at 18:36 ----------
I have just modified the single line in your program.
Try with the following code.
In your program you have declared the char pointer BUFFER as a global pointer.
And you are calling the function in printf().
printf() is right associative.So STRREVERSE("jill") will be called first then STRREVERSE("jack") then STRREVERSE("john").
So finally the pointer BUFFER will have the reversed string of john only.
And The function STRREVERSE is returning char pointer(char *).
So the return value of the three function calls will be pointing the same address.(address of BUFFER).
BUFFER contains reversed string of john only.
So the value "nhoj" will get printed for three times.
So I have declared the BUFFER as a local pointer.
Last edited by kiruthika_sri; 03-18-2010 at 01:34 AM..
printf() is right associative.So STRREVERSE("jill") will be called first then STRREVERSE("jack") then STRREVERSE("john").
Ah really? Unless I am mistaken, the ANSI-C standard leaves the order of parameters evaluation up to the compiler ("it's unspecified"). This can be left-to-right, or right-to-left or anything else the compiler may find convenient.
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