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# 1  
Old 04-01-2008
date
file1
E108,0,2/3/1995,0,E001,E003,A,15000,1250,7.211538,12/14/2008
E109,0,2/15/1995,0,E001,E001,A,78000,6500,37.5,2/3/1995



resultant date should be in this formate
E108,0,199523,0,E001,E003,A,15000,1250,7.21153820081214
E109,0,1995215,0,E001,E001,A,78000,6500,37.5,199523


Is the any command or code that would do this .........please replay asap........
Identifing the date values in the each row cutting dd mm yyyy separately and arranging in this order yyymmdd.........is there any command that do or code.......
# 2  
Old 04-01-2008
nawk -f char.awk myFile

char.awk:
Code:
BEGIN {
  FS=OFS=","
}
{
  split($2, a, "/")
  $2=a[3] a[1] a[2]

  split($NF, a, "/")
  $NF=a[3] a[1] a[2]
  print
}

# 3  
Old 04-01-2008
Might want to rethink the original request.

How would you interpret 2008111

is it january 11th or November 1st.

fortunately the awk statment could be modified to handle converting to
20080111 or 20081101 - respectively.
# 4  
Old 04-01-2008
hi
Quote:
Originally Posted by vgersh99
nawk -f char.awk myFile

char.awk:
Code:
BEGIN {
  FS=OFS=","
}
{
  split($2, a, "/")
  $2=a[3] a[1] a[2]

  split($NF, a, "/")
  $NF=a[3] a[1] a[2]
  print
}


it is not working


$ cat > char.awk
BEGIN {
FS=OFS=","
}
{
split($2, a, "/")
$2=a[3] a[1] a[2]

split($NF, a, "/")
$NF=a[3] a[1] a[2]
print
}
^D$
$ sh char.awk
char.awk[1]: BEGIN: not found
char.awk[3]: syntax error: `}' unexpected
$
# 5  
Old 04-01-2008
hi,problem with nawk
Quote:
Originally Posted by vgersh99
nawk -f char.awk myFile

char.awk:
Code:
BEGIN {
  FS=OFS=","
}
{
  split($2, a, "/")
  $2=a[3] a[1] a[2]

  split($NF, a, "/")
  $NF=a[3] a[1] a[2]
  print
}


$ awk -f char.awk myfile > out7
$ cat out7
E108,0,2/3/1995,0,E001,E003,A,15000,1250,7.211538,20081214
$ gawk -f char.awk myfile > out7
$ cat out7
E108,0,2/3/1995,0,E001,E003,A,15000,1250,7.211538,20081214
$ nawk -f char.awk myfile > out7
-bash: nawk: command not found
$


with awk only the last column of the file is changing.......
# 6  
Old 04-01-2008
sorry:
Code:
BEGIN {
  FS=OFS=","
}
{
  split($2, a, "/")
  $3=a[3] a[1] a[2]

  split($NF, a, "/")
  $NF=a[3] a[1] a[2]
  print
}

# 7  
Old 04-01-2008
Just a touch-up
Code:
#cat char.awk 
BEGIN {
  FS=OFS=","
}
{
  split($3, a, "/")
   if (a[1]<10) a[1]=0a[1]
   if (a[2]<10) a[2]=0a[2]
  $3=a[3] a[1] a[2]

  split($NF, a, "/")
   if (a[1]<10) a[1]=0a[1]
   if (a[2]<10) a[2]=0a[2]
  $NF=a[3] a[1] a[2]
  print
}

Last edited by danmero; 04-01-2008 at 04:31 PM.. Reason: Fix typo
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