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Converting the date format

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# 1  
Old 05-07-2011
Java Converting the date format
Hi All,

I am new to this forum. Could anyone help me to resolve the following issue.

Input of the flat file contains several lines of text for example find below:
Code:
5022090,2,4,7154,88,,,,,4/1/2011 0:00,Z,L,2
5022090,3,1,6648,88,,,,,4/1/2011 0:00,Z,,1
5022090,4,1,6648,88,,,,,4/1/2011 0:00,Z,,1

output:
Code:
5022090,2,4,7154,88,,,,,01-Apr-2011,Z,L,2
5022090,3,1,6648,88,,,,,01-Apr-2011,Z,,1
5022090,4,1,6648,88,,,,,01-Apr-2011,Z,,1


I am using a client server using putty.


Information:

This is for one particular flat file while in other flat files the date field may contain at some other column the column of the date field is not common to all the flat files..
Last edited by radoulov; 05-07-2011 at 07:18 AM.. Reason: Code tags, please!
# 2  
Old 05-07-2011
Quote:
I am using a client server using putty.
Putty is a terminal emulator, it can talk to anything, knowing you use putty isn't useful.

To find out what your system is, try uname and uname -a. What tools you have available may be very different on different systems.
# 3  
Old 05-07-2011
Hi,

Thanks for the response

I have tried the following it thrown me this:
Code:
 
$ uname
SunOS

$ uname -a
SunOS cdrp06 5.8 Generic_117350-38 sun4u sparc SUNW,Sun-Fire

Could you please give me the code which converts the date format from the flat file as specified in the previous post
Last edited by Scott; 05-08-2011 at 09:40 AM.. Reason: Code tags
# 4  
Old 05-08-2011
Some pointers
since you say that in each file, the column no, containing the date may be different, the fist thing is that you program/script must take the file name and column number as arguments.

I would use "awk" (my favourite filter) called from a shell script by:
<Shell script> <FileName> <ColumnNo>
Within the shell script
awk 'A=$1 b=$2 {awk script} ;;;

In the example, it is the 10 th field (when separated by commas).

For each line:
-- Split the 10th filed into an array using "split" function"
-- Replace the month with the appropriate text (if .. else ..)
-- Write the first 9 fields, the rearranged 10 filed and any other fileds.


OK
# 5  
Old 05-08-2011
Try this, this should work if date is present in any column

Code:
awk -F"," '{for(i=1;i<NF;i++){t=match($i,/:/,_1);
if(t!=0){_2="date -d \""$i"\" +'%d-%h-%Y'"; _2|getline _d;$i=_d;print}} }' OFS="," inputfile

regards,
Ahamed
# 6  
Old 05-08-2011
Got perl?
Code:
perl -F, -ane '{ 
  @mons=qw(Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec) ; 
   foreach(@F) { 
      if(/(\d{1,2})\/(\d{1,2})\/(\d{4})/) {
          $_="$2-$mons[$1-1]-$3";
      } 
   } 
print join(",",@F);}' input

# 7  
Old 05-09-2011
Java Perl worked
Hi Mirni,

Thanks for the code it got worked perfectly. Smilie Smilie
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