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Shell Programming and Scripting

AWK program

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# 15  
Old 03-19-2009
Code:
awk '{printf "%s ",$5} ' file*  |   tr ' ' '\n' | while read a; do read b; echo "$a $b"; done

# 16  
Old 03-19-2009
Quote:
Originally Posted by aaaaargh
Code:
awk '{printf "%s ",$5} ' file*  |   tr ' ' '\n' | while read a; do read b; echo "$a $b"; done

i don't think this will work Smilie
# 17  
Old 03-19-2009
Error
Sorry for the late reply (meetings... Smilie )

(assume awkscript filename = SmellsLikeHomeWork.awk)

Code:
{
  if (c!=FILENAME) { c=FILENAME ; i++ ;j=0 }
  a[i,++j] = $5
}


END {
    for( n=1 ; n<=j ; n++)
    {
      for( m=1 ; m<=i ; m++ )
      {
        printf("%s ",a[m,n]);
      }
      printf("\n");
    }
}

Usage: nawk -f SmellsLikeHomeWork.awk file1 file2 file3 file4
# 18  
Old 03-19-2009
This should do:

Code:
awk '{print $5}' $(ls -1 file* |sort -n -k1.5) |pr -t -s" " -184

184 is the no. of files. The reason behind the "$(ls -1 file* |sort -n -k1.5)" is to get the files in correct alphabetical order (it skips 'file' and sorts on 1, 2, 3...). If your filenames are not following a regular pattern, then you may need to put them manually in the correct order like this:

Code:
awk '{print $5}' f1 file2 filename3 |pr -t -s" " -3

# 19  
Old 03-19-2009
MySQL
Quote:
Originally Posted by rikxik
This should do:

Code:
awk '{print $5}' $(ls -1 file* |sort -n -k1.5) |pr -t -s" " -184

184 is the no. of files. The reason behind the "$(ls -1 file* |sort -n -k1.5)" is to get the files in correct alphabetical order (it skips 'file' and sorts on 1, 2, 3...). If your filenames are not following a regular pattern, then you may need to put them manually in the correct order like this:

Code:
awk '{print $5}' f1 file2 filename3 |pr -t -s" " -3

SmilieSmilie
great.. i couldn't remember that "pr" command Smilie
# 20  
Old 03-19-2009
Smilie I don't think its used often but sometimes its just what you need.
# 21  
Old 03-19-2009
Thanks!
Thanks to you all for working so hard to help me!
Smilie
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