Shell Programming and Scripting

Hey Guys....
Just need some help as I am not proficient in Unix shell script...
Doubt:
---------------
Suppose there will be some of the following files inside a directory called OUT ...

Path: - /appdb1/product/batch/rms/OUT

files inside OUT directory:-
POSU_75002_20090127_20090129035442
POSU_75002_20090127_20090128035145
POSU_75002_20090127_20090129035442

I want a script which will rename these files and put an extension of .1, .2, .3, .4, .5, .6 .................respectively till whatever number of POSU files it will be there inside the OUT directory.....

I just know that mv $LINE $LINE.1 will rename the file to .1 ext but i want the above outputs.....

Try this

Code:

cnt=1
for file in `ls /appdb1/product/batch/rms/OUT/` ; do
    mv ${file} ${file}.${cnt}
    cnt=$(( cnt +1 ))
done

Satyajit,

Try this.

Code:

 
# count the number of POSU files, assuming the file names start with POSU
fc=`ls POSU* | wc -l`
ls POSU* > /tmp/file_list.txt
i=1
while read line
do
  if [[ ${i} -gt ${fc} ]]; then
    break;
  fi
  mv ${line} ${line}.${i}
  i=$(( ${i} + 1 ))
done < /tmp/file_list.txt

HTH,

Regards,

Praveen

Thanks pludi and Praveen ....

Both the scripts are working.....

In pludi's solution i added just one word (POSU*) and it worked...

cnt=1
for file in `ls -ltr /appdb1/product/batch/rms/OUT/POSU*` ; do
mv ${file} ${file}.${cnt}
cnt=$(( cnt +1 ))
done

Thanks again for your help guys....
Hey I have one more question...altough this is totally diff from the topic...

How can we delete all the files except for the last 3 days files ????

Code:

find <path> -type f -mtime +3 -exec rm '{}' ';'

Explanation: find all files (-type f) in <path>, not modified in the last 24*3 hours, and pass them as an argument to rm.
I suggest you try it with mv or -print first, to see if it captures those files you want, before feeding them straight to rm.