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Printing out multiple lines with a correct format

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# 1  
Old 02-05-2009
Printing out multiple lines with a correct format
Hello,
This is my first post and I've just started on UNIX in school.

A file name "list" has the following content (excluding the numbers and the bottom part):
Code:
          1         2         3         4         5         6
0123456789012345678901234567890123456789012345678901234567890
IT         Karen Patel    Wimps        Ranjit Singh   FULL
EngineeringKaren Thompson Vegans       John Thompson  PART
Marketing  Ken Whillans   Eagles       Karen Thompson FULL

Names: 11-26
Team Name: 27-39
Partner: 40-53

What I want to do is to output the player's name with the partner's name right next to it. This is what I've done so far:
Code:
echo "Player name?"
	read player 
name=`grep $player........................... list | cut -c12-26 | sed 's;^ *;;;s; *, *;,;g;s; *$;;'`
		target=`grep $player........................... list | cut -c40-54 | sed 's;^ *;;;s; *, *;,;g;s; *$;;'`
		if [ $(echo $name | wc -w) -eq 0 ]
		then
			echo "No such player."
		else
			echo -e "$name's target is $target.\n"
		fi

When the user puts "K" as the player's name, I want the output in this format:
Code:
Karen Patel's partner is Ranjit Singh.
Karen Thompson's partner is John Thompson.
Ken Whillans 's partner is Karen Thompson.

but the output that I get is:
Code:
Ken Whillans
Karen Thompson
Karen Patel's team name is Eagles
Vegans
Wimps.

How can I fix this problem?
Thank You.
# 2  
Old 02-05-2009
Please read the forum rules, you should not post homework(s) Smilie
Code:
# cat file
IT         Karen Patel    Wimps        Ranjit Singh   FULL
EngineeringKaren Thompson Vegans       John Thompson  PART
Marketing  Ken Whillans   Eagles       Karen Thompson FULL

# while read line;do echo "${line:11:14} 's partner is ${line:39:15}"| sed 's.  . .g;s.  . .g;s. $.\..';done <file
Karen Patel 's partner is Ranjit Singh.
Karen Thompson 's partner is John Thompson.
Ken Whillans 's partner is Karen Thompson.

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