Shell Programming and Scripting

I've got the output you've shown. But the real problem starts when you give some variable instead of 20.

I think I can give myself the Idiot of the week award

The solution is

Code:

read fs

du -a <folder> | nawk '$1 > fs {print $0}' fs=$fs

Sorry Zaxxon for the trouble . Thanks Murphy for the info.

No problem ^^

Well now that I've got my result. I want to try out something here. Suppose I want the file size (column 1 of my output) to be printed in human readable form, How do I go about it??

performing the same operation on du -ah is not an option as we saw earlier. Please help out.

Code:

Sample Output 


28314   .
28170   ./OMautomation
27926   ./OMautomation/pqms
26096   ./OMautomation/pqms/EDM_Batch20080907.log
1744    ./OMautomation/pqms/REDX20080907.log

Just add something like "k" to the print statement, whatever is appropriate.

Well if that's the only solution, its a little more complicated than a k, If I do a division by 1024 once, i need to append K, twice, by M, and thrice, by G and so on.

That's why I was looking for an alternative.

Why complicated? Either choose the best suitable size and write it fix to the print ie. multiply.
Or check the length with "length($1)" and if it's some size, apply the multiplier for the size you want.
I personally would choose the way to present a fix size. People that work with computers on the shell should be able to count the number of digits, but that's just my point of view

Another possibility is to use another switch for du, if your's can do this like -m or something and then strip the the M off $1 and assign it to a variable, do your comparison and then just put it back to $1 when printing the output.