loop because of using 'sort -k 2'


 
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# 1  
Old 01-28-2009
loop because of using 'sort -k 2'

Hallo,

I have a problem with the sort command:
When I run the following in a shell, it works fine:
Code:
tail -n 2 file.txt | sort -k 1

I tried it under severel shells: c-shell, borne-shell, bash
I get the output I want to have.

But when I use it in my script, I get a mysterious error: I have a menu like this one:
Code:
#!/bin/sh
stop="yes"
while [ $stop = "yes" ]
do
  printf "Select one (1/2/q): "
  read inputkey
  case $inputkey in
    1) echo "you sayed 1"
       tail -n 2 results.txt | sort -k 1;;
    2) echo "you sayed 2"
       tail -n 2 results.txt | sort -k 2;;
    q) echo "you sayed q"
       stop="no";;
    *) echo "You have to select between 1 and 2";;
  esac
done

No I sayed 1 for example - and then there is an unending loop of the asterisk-option:
Code:
Select one (1/2/q): 2
you sayed 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
...

(When I sayed 1, I get the normal output)

What error can that be?
# 2  
Old 01-28-2009
The first thing that stands out to me, is that I would put double quotes around $inputkey on the case line.

Code:
case "$inputkey" in 
...

I've had similar errors before that were fixed by this.
# 3  
Old 01-28-2009
Quote:
Originally Posted by rwuerth
The first thing that stands out to me, is that I would put double quotes around $inputkey on the case line.

Code:
case "$inputkey" in 
...

I've had similar errors before that were fixed by this.

That will make no difference; case $var in is one of the few instances where the variable does not need to be quoted.
# 4  
Old 01-28-2009
Okay, i set it in double qoutes:
Code:
stop="yes"
while [ $stop = "yes" ]
do
  printf "Select one (0/1/2/q): "
  read inputkey
  case "$inputkey" in
    0) echo "you sayed 0"
       tail -n 2 results.txt;;
    1) echo "you sayed 1"
       tail -n 2 results.txt | sort -k 1;;
    2) echo "you sayed 2"
       tail -n 2 results.txt | sort -k 1;;
    q) echo "you sayed q"
       stop="no";;
    *) echo "You have to select between 1 and 2";;
  esac
done

But there's still the same error
# 5  
Old 01-28-2009
Quote:
Originally Posted by wiseguy
Hallo,

I have a problem with the sort command:

Your problem has nothing to do with sort.
Quote:
When I run the following in a shell, it works fine:
Code:
tail -n 2 file.txt | sort -k 1

I tried it under severel shells: c-shell, borne-shell, bash
I get the output I want to have.

But when I use it in my script, I get a mysterious error:

You are not getting an error from the sort command.
Quote:
No I sayed 1 for example - and then there is an unending loop of the asterisk-option:
Code:
Select one (1/2/q): 2
you sayed 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
Select one (1/2/q): You have to select between 1 and 2
...

(When I sayed 1, I get the normal output)

What error can that be?

There is no error message there. Did you forget to post it?

Are you redirecting your input?

Try:

Code:
read inputkey < /dev/tty

# 6  
Old 01-29-2009
Okay, that "</dev/tty" is a good idea - i thought that works without that, but now I know thats better to do ;-)

But the Problem with my sort command isn't solved:
I get nothing from it, but when I run that in shell, I get what I want.

Now I tried that with "set -x":
Code:
stop="yes"
while [ $stop = "yes" ]
do
  printf "Select one (0/1/2/q): "
  read inputkey < /dev/tty
  case $inputkey in
    0) echo "you sayed 0"
       tail -n +2 results.txt;;
    1) echo "you sayed 1"
       set -x
       tail -n +2 results.txt | sort -k 2
       set +x;;
    2) echo "you sayed 2"
       tail -n +2 results.txt | sort -k 2;;
    q) echo "you sayed q"
       stop="no";;
    *) echo "You have to select between 1 and 2";;
  esac
done
exit

And now I run this:
Code:
Select one (0/1/2/q): 1
you sayed 1
+ sort -k 2
stop=yes
+ [ yes = yes ]
+ printf Select one (0/1/2/q):
+ tail -n +2 results.txt
Select one (0/1/2/q): + read inputkey
q
+ echo you sayed q
you sayed q
stop=no
+ [ no = yes ]
+ exit
+ set +x
Select one (0/1/2/q): q
you sayed q
$

There is anything wrong:
After using sort, the script have a "not understanding behavior"... Smilie

my "results.txt" has this lines (for testing):
Code:
year month
1990 56
1991 1
1992 90

[EDIT]
Maybe I show You the "normal" output from "tail -n +2 results.txt | sort -k 1" in the shell:
Code:
$  tail -n +2 results.txt | sort -k 2
1991 1
1990 56
1992 90
$


Last edited by wiseguy; 01-29-2009 at 03:21 AM.. Reason: I changed now "tail -n 2" to "tail -n +2" and "sort -k 1" to "sort -k 2"
# 7  
Old 01-29-2009
Okay, now I get it: I had this all in a function named "sort" ... Smilie
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