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Replacing data of output file with input

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# 8  
Old 01-29-2009
I took your point to note and i did little home work.... Comm command compares 2 files... i just dont want comparsion.... actually what i want is replacing....
ie for example... in time.out file there is alread data for date 25 now read.out again got 25.... i want to replace the data of 25 in time.out with runtime.out irrespective of there being any change in the data... and if there is no 25 in time.out then write it .... thats excatly what i want....Please say me that there some way i can do this and help me out... please....
# 9  
Old 01-29-2009
If I understand your question correctly, you want to search for the date in time.out and if it is present, update it with the line from runtime.out or append to time.out, you may try the below code:
Code:
tr -d '\n' < runtime.out >temp.out
grep -q $CUR_MAINT_DATE time.out
if [ $? -eq 0 ]
   echo |cat time.out -|sed "s/^$CUR_MAINT_DATE.*/`cat temp.out`/"|awk '{ if( NR==1 ) printf $0; else printf "\n" $0; }'
else
  #append code
fi

This may be easier if you can have newline at the end of time.out file:
Code:
sed "s/^$CUR_MAINT_DATE.*/`cat temp.out`/" time.out

# 10  
Old 01-29-2009
The code you gave almost work but there one problem....
i added appened and then to if and the code is like this....
Code:
read.ksh `basename ${0}` $1 $2 ${CUR_MAINT_DATE} > runtime.out
tr -d '\n' < runtime.out >temp.out
grep -q $CUR_MAINT_DATE time.out
if [ $? -eq 0 ]
then
   echo |cat time.out -|sed "s/^$CUR_MAINT_DATE.*/`cat temp.out`/"|awk '{ if( NR==1 ) printf $0; else printf "\n" $0; }'
else
  tr -d '\n' < runtime.out >> time.out;echo >> time.out
fi

Actually read.ksh is called by Mail.ksh
when i run Mail.ksh i get output like this
Code:
 ./Mail.ksh 1 1
Current maintenance date is 20090126
20090124,00:02:26,00:04:19,86752,00:01:37,00:02:50,01:07:52,150818, ,
20090125,00:02:31,00:00:11,2776,00:01:38,00:01:31,00:56:36,108938, ,
20090126,00:02:33,00:00:35,8187,00:01:42,00:01:32,02:02:08,321055, ,
20090127,00:02:33,00:03:04,62153,00:01:39,00:02:25,01:39:55,266355, ,
Current maintenance date is 20090127
20090124,00:02:26,00:04:19,86752,00:01:37,00:02:50,01:07:52,150818, ,
20090125,00:02:31,00:00:11,2776,00:01:38,00:01:31,00:56:36,108938, ,
20090126,00:02:33,00:00:35,8187,00:01:42,00:01:32,02:02:08,321055, ,
20090127,00:02:33,00:03:04,62153,00:01:39,00:02:25,01:39:55,266355, ,
Current maintenance date is 20090128

where i have to get like this
Code:
 ./Mail.ksh 1 1
Current maintenance date is 20090126
Current maintenance date is 20090127
Current maintenance date is 20090128

where all the curent ma... statement is comming becaue i have an echo... which i will remove later...
Ofcose its working as it is appeneding a new line to my time.out at the end ie 28... but i dont know if its replaceing 26 and 27 in time.out... as they are same...for time being...i will test that later with more data...
But please help me in removing this print or echo statement thats comming when i execute the script

Thanks

Bhagya
# 11  
Old 01-29-2009
I made few changes and i got the result as i want.... Thanks a lot for being there for me
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