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using bc with floating point number in files

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# 8  
Old 01-28-2009
Quote:
Originally Posted by pludi
The first one should work, since the tr takes care of the newline. If the file is generated with MS-DOS/Windows style line terminators, modify the line to read
Code:
cat file | tr '\r' ' ' |tr '\n' '/'|sed -e 's#/$#\n#'

This wont work because sed requires the input to already have a newline in it to process the line. The line coming out of the tr command does not contain a new line, so sed will ignore it.

What you can do is this

Code:
 
echo $(sed -e 's#$#\#') 1.0 | bc -l

vgersh99 had a post on this yesterday. If I figure out how to make a nice link I'll put it here.
# 9  
Old 01-28-2009
Go to This link for vgersh99's description of how this works.
# 10  
Old 01-28-2009
I get
Quote:
sed: command garbled: s#$#\#
1.0
# 11  
Old 01-28-2009
Given the myFile content like so:
Code:
196.304492
615.348986

.....
Code:
#!/bin/ksh

echo "scale=10;$(tr '\n' '/' < myFile;)1"|bc

# 12  
Old 01-28-2009
From the link you gave me
Quote:
echo $(sed -e 's/$/+/' tmp.tmp1) 0 | bc
works fine if I need the sum, but not the ratio... (replacing + with / doesn't work)
# 13  
Old 01-28-2009
Quote:
Originally Posted by vgersh99
Given the myFile content like so:
Code:
196.304492
615.348986

.....
Code:
#!/bin/ksh

echo "scale=10;$(tr '\n' '/' < myFile;)1"|bc

finally it worked, thank you all!
# 14  
Old 01-28-2009
Quote:
Originally Posted by f_o_555
From the link you gave me


works fine if I need the sum, but not the ratio... (replacing + with / doesn't work)
And you changed the zero to a one?

Also, if using the s/ / / delimiter did you escape the division operator?

's/$/\//'
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