The delimiter provided in cut statement is not used in the variable. Also, when we give f1 or f3 or f10 or any other field instead of f2, we still get the output 2009-01-16.
I don't get it - even if he did, when you call the value of the variable with echo, the " are gone anyway using them like in your snippet. So there will be still nothing to cut out.
I mean I don't want to take your happyness away heh
I am using : << cut / cut to comment out block of code.
Works fine on few lines of script, then it gives me this cryptic error when I try to comment out about 80 lines.
The "warning " is at last line of script.
done < results
169 echo "END read all positioning parameters"
170... (8 Replies)
I'm a complete beginner in UNIX (and not a computer science student either), just undergoing a tutoring course. Trying to replicate the instructions on my own I directed output of the ls listing command (lists all files of my home directory ) to My_dir.tsv file (see the screenshot) to make use of... (9 Replies)
Hi
Can anyone what I am doing wrong while using cut command.
for f in *.log
do
logfilename=$f
Log "Log file Name: $logfilename"
logfile1=`basename $logfilename .log`
flength=${#logfile1}
Log "file length $flength"
from_length=$(($flength - 15))
Log "from... (2 Replies)
01-22-2009
