how to read only the first two values from a file in unix


 
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# 1  
Old 01-19-2009
how to read only the first two values from a file in unix

Hi,
I'm new to unix.. I need to read only the first two values from a file that contains many data....My record is like this

FTG_ver_num=7.0
RUN_ID=2
$$tgt_envrnmt_cd=FTG
$$WRK_FLW_CD=NPL

I need oly the values of ETG_ver_num and RUN_ID.
i.e) output to be 7.0 and 2

The code i used is:

awk -F\:= '{print $1, $2}' filename |\
while read ETG_ver_num RUN_ID
do
echo "$ETG_ver_num"
echo "$RUN_ID"
done

The Output i get is
FTG_ver_num=7.0
RUN_ID=2
$$tgt_envrnmt_cd=FTG
$$WRK_FLW_CD=NPL

But i want only the first two.. kindly help me on this.
# 2  
Old 01-19-2009
Code:
awk -F"=" 'NR<3 {print $2}'  filename

# 3  
Old 01-19-2009
Thanks

Thanks Krish its working fine
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