Shell Programming and Scripting

I have a file with millions of rows that I need to add a delimiter and a new field with a zero to the end of each row. (its too big to open and do a find and replace regex)

I'm looking for the next line '\n' and need to replace it with a Unit Separator (hex \037) 0 \n.

I've tried the following:
sed -e "s/[\012]/[\037]0[\012]/g" testin.txt > testout.txt

and

sed -e 's/'$(echo "\012")'/'$(echo "\037")'0'$(echo "\012")'/g' testin.txt > testout.txt

neither of these are working. Any ideas?

Is this what you are trying to do?

Code:

> cat file140
line1
line2
line3
> cat file140 | od -An -t oC -w10
 154 151 156 145 061 012 154 151 156 145
 062 012 154 151 156 145 063 012
> awk '{print$0"\037""0"}' file140 >file140.out
> cat file140.out | od -An -t oC -w10
 154 151 156 145 061 037 060 012 154 151
 156 145 062 037 060 012 154 151 156 145
 063 037 060 012

I think I've got it figured out. Instead of looking for the \n, I can just look for the end of row ($). Here's the statement.

sed 's/$/\x1f0/' testin.txt > testout.txt