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grep tomorrow's date

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# 1  
Old 01-09-2009
grep tomorrow's date
Hi guys,

I need to find tomorrows date in date fomat and should be in variable.
as I need to grep this date in a flat file

ie. if today's date is '09 JAN 2009'

output should be '10 JAN 2009'

unix/perl script will be fine.
# 2  
Old 01-09-2009
date | awk '{print $1,$2,$3 + 1,$4}'


From....


simon@cartman:~$ date
Fri Jan 9 15:09:45 GMT 2009
simon@cartman:~$ date | awk '{print $1,$2,$3 + 1,$4}'
Fri Jan 10 15:09:46
simon@cartman:~$
# 3  
Old 01-09-2009
Just realised....You would of course have to wrap this in a if statement to ensure the dates, months, years roll.

A better way would be to increment the unix time stamp by the correct integer (seconds in 24 hours), and then convert to the normal date.
# 4  
Old 01-09-2009
Thanks for your quick reply

I am gettting the output as

Fri Jan 10 10:16:39 -- 10th Jan is SAT

but i need

10 Jan 2009 format.
# 5  
Old 01-09-2009
Code:
myvar=`date '+%d %b %Y' --date="next day"`
echo $myvar

Code:
myvar=`date '+%d %b %Y' --date='1 days'`
echo $myvar

Code:
myvar=`date '+%d %b %Y' --date="tomorrow"`
echo $myvar

Code:
myvar=` date '+%d %b %Y' --date="-1 days ago"`
echo $myvar

Last edited by Ikon; 01-09-2009 at 11:40 AM..
# 6  
Old 01-09-2009
If you have GNU date:

Code:
$ date --version
date (coreutils) 5.2.1
Written by David MacKenzie.

Copyright (C) 2004 Free Software Foundation, Inc.

$ date -d 'tomorrow' +'%d %b %Y'
10 Jan 2009

# 7  
Old 01-09-2009
Working !!
Hello All,

'snoop2048' solutions is working after some changes.

`date | awk '{print $3 + 1,$2,$6}'`

Thank you all for your quick response. Appreciated !!!Smilie

Have a great Weekend !!!
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