Shell Programming and Scripting

I need some help to run this executable from within a shell script.

The Script is run the following way at the command prompt.

$rateupd
Main Menu --Standard Output
----------- --Standard Output
1. - Update Rate --Standard Output
2. - Exit. --Standard Output

Enter Selection: 1 --User Input

Beginning Rate Update Process

Enter Rate Data Source: xxsource --User Input
Enter Rate Server Name: xxserver --User Input
Enter Rate User ID: xxuser --User Input
Enter Rate User Password: xxpasswd --User Input
Enter the Path of the update file: /aaa/bbb/load_file.txt --User Input

Rate Update Successful. --Standard Output

I would like to know if it is possible to run the above script by passing those inputs from within a shell script.

Any help is greatly appreciated.

use 'select' to create your 'Menu'
use 'read' to read user input.

Vgresh99

In my post 'rateupd' is the executable that is being run.

I want to wrap it in a shell script where I can pass 'rateupd' the varibles which it reads from the input.

Since the partmeters (Input variables) for 'rateupd' are sequentially read from the input. I want to know is there any way I can run 'rateupd' from within the wrapper shell.

yes, that's why the 'wrapper' script is called 'wrapper' - it 'wraps' the already existing utility with the 'simplifying' calling logic.

I do not want the shell to prompt me to enter something at the input. I want the hardcoded variables to be passed within the shell. Is that possible? I thought there was some way to collect keystrokes in a file and pass it to the executable (In this case rateupd). I have never done it. I just needed an example so that I can use it.

you can try something like this with the here-doc:

Code:

#!/bin/ksh

rateupd <<EOF
1
xxsource
xxserver
xxuser
xxpasswd
/aaa/bbb/load_file.txt
EOF