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find PHRASE and PATH

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# 1  
Old 01-07-2009
find PHRASE and PATH
I've got a script which finds *.txt files in directories and subdirectories after providing the path by the user and then searches in the files for phrase given by the user

Quote:
#!/bin/bash
PATH_BIN=/bin
PATH_USR=/usr/bin
DIRECTORY=$1
PHRASE=$2
echo "";
read -p "Provide path to directory to find *.txt: " DIRECTORY
read -p "State what phrase you're looking for in the files *.txt: " PHRASE

function PHRASE_ {
if [ $PHRASE ];
then
echo "";
FOLDERS_=`$PATH_USR/find $DIRECTORY -name *.txt -print`
WRITE_=`$PATH_USR/find $DIRECTORY -name *.txt -print | $PATH_USR/xargs $PATH_USR/catdoc -a | $PATH_BIN/grep -n "$PHRASE"`
echo "$WRITE_" >> ${PATH}/temp/write_values.txt
exit -1;
# echo "The PHRASE is in : " ${FOLDERS_};
else echo "The PHRASE does not exist *.txt"
fi;
}
PHRASE_
How to write script in such way that the paths to the found *.txt files and the phrase given by the user were both displayed ?

For example:

Quote:
$./script.sh
Provide path to directory to find *.txt: /home/przemek/tempowy/find_txt/Catalogue
State what phrase you're looking for in the files *.txt: <value>
/home/przemek/tempowy/find_txt/Catalogue/data/common/file.txt
<value>
/home/przemek/tempowy/find_txt/Catalogue/data/common/tools/file.txt
<value>
...
# 2  
Old 01-07-2009
I usually hack my way through this as follows:
Code:
find $DIRECTORY -name *.txt -print | 
while read file; do
   echo $file
   $PATH_USR/catdoc -a $file | grep -n "$PHRASE"
done

But that leaves you with files being printed out that don't contain PHRASE. So you could do this, which requires a catdoc and grep for each file:
Code:
find $DIRECTORY -name *.txt -print | 
while read file; do
   if catdoc -a $file | grep "$PHRASE" >/var/tmp/phrase-grep-$$ ; then 
     echo $file
     cat /var/tmp/phrase-grep-$$
     rm -f /var/tmp/phrase-grep-$$
   done
done

# 3  
Old 01-07-2009
Thank you very much Smilie
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