Shell Programming and Scripting

Here is a sample of the desired output

"
0.020064
0.522624
1.00656
8.058944
"

based on this input:

"
- 0.020064 0 1 tcp 40 ------- 1 0.0 6.0 0 0
r 0.020064 1 2 tcp 40 ------- 1 0.0 6.0 0 0
r 0.020067 1 2 tcp 40 ------- 1 0.0 6.0 0 0
...
+ 0.522624 5 6 tcp 40 ------- 2 7.0 6.1 0 1
r 0.522624 1 5 tcp 40 ------- 2 6.1 7.0 0 12
r 0.522625 1 5 tcp 40 ------- 2 6.1 7.0 0 12
...
+ 0.998912 5 6 tcp 1040 ------- 3 8.0 6.2 1 21
r 1.00656 1 2 tcp 40 ------- 4 6.3 9.0 1 26
r 1.00657 1 9 tcp 40 ------- 4 6.3 9.0 1 26
...
r 8.058944 1 5 tcp 1040 ------- 2 7.0 6.1 52 883
r 8.058944 5 6 tcp 1040 ------- 2 7.0 6.1 52 883
r 8.062336 1 6 tcp 1040 ------- 5 10.0 6.4 200 837
"

This is actually the output of an ns-2 simulation, the $2 represents the time. So what I basically want is only the time values that have the form *.0* or *.5* and they have $3==1. Moreover, if there are more than one values with this quality, say 8.058944 and then 8.063296, I only want the first 8.0* value, in this case 8.058944. And this goes also for all the other values (0.0*, 0.5*, 1.0*, 1.5*, ..., 8.0*, 8.5*)

Thanks

If I don't misunderstand the question:

Code:

awk '{f=substr($2,1,3)} f!=s && $3==1{s=f;print $2}' file

Regards

it worked, thank you very much Franklin52 and everybody who answered

Ah reread everything... Saw franklin's solution.
I thought that the 2nd column wasn't necessarily sorted....
so i came up with:

Code:

nawk '{
  if ( $2 ~ /\.[05]/ && $3 == 1 ){
    idx = sprintf( "%0.01f", $2 );
    if ( ! hash[idx] ){
      hash[idx] = $2;
      }
    }
  }
  END{
  for ( idx in hash ){
    print hash[idx];
    }
  }'

The previous solution wouldn't handle 13.0 and 13.5 correctly.... btw....

thank you, gonna revise the issue,though my problem was mostly solved with the previous suggestion.

regards