How to check the variable is present in array or not ?

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How to check the variable is present in array or not ?

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01-04-2009

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How to check the variable is present in array or not ?

Hi ,

I am trying to check wether the variable is present in the array. please see the below code .when ever i do this its taking only the first value of the array . please advise.

###Code Snnipet ###

#!/bin/ksh

set -xv

if [[ -n $1 ]]; then

echo " you have Specified the ORG ID - $1 "

else

echo " Please specify a valid three digit GNS-ORG-ID "

exit 1

fi

ORG=$1

set -A ORGID 211 233 244 300 143 234 222 564 586 810 975

#echo "${#ORGID[*] }"
#echo "${ORGID [2] }"

printf ${ORGID[*]}

if [[ $ORG == ${ORGID[*]} ]]; then <== Here its checking only with first value of the array ####
echo " Its a valid ORG ID "

else

echo " Its INVALID ORG ID - $1 "

echo " Please specify a valid ORG ID "

exit 1

fi

padhu.47

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01-04-2009

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Quote:

Originally Posted by padhu.47

Hi ,

I am trying to check wether the variable is present in the array. please see the below code .when ever i do this its taking only the first value of the array . please advise.

When posting code, please put it between [code] tags and post enough to demonstrate your problem, but no more.

Quote:

Code:

###Code Snnipet ###

#!/bin/ksh

set -xv

if [[ -n $1 ]]; then

echo " you have Specified the ORG ID - $1 "

else

echo " Please specify a valid three digit GNS-ORG-ID "

exit 1

fi


ORG=$1


set -A ORGID 211 233 244 300 143 234 222 564 586 810 975



#echo "${#ORGID[*] }"
#echo "${ORGID [2] }"

printf ${ORGID[*]}

if [[ $ORG == ${ORGID[*]} ]]; then    <== Here its checking only with first value of the array ####

case ${ORGID[*]} in
*"$ORG"*) echo valid ;;
*) echo Invalid ;;
esac

Quote:

Code:

echo " Its a valid ORG ID "

else

echo " Its INVALID ORG ID - $1 "

echo " Please specify a valid ORG ID "

exit 1

fi

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