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Shell Programming and Scripting

Cron wait on dynaminc trigger file

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# 1  
Old 12-30-2008
Cron wait on dynaminc trigger file
I have to schedule a script in cron that watch for a trigger file named as xyz_extract_file_20081201.null (the YYYYMMDD portion would change every day). The wait/wakeup time would be 1 min and the date portion will always be current date (Eg., the trigger file named as xyz_extract_file_20081201.null will be watched on 20081201). The timeout must happen after 8 hours. Could you please help me with a shell script?
# 2  
Old 12-30-2008
Quote:
Originally Posted by shekharaj
I have to schedule a script in cron that watch for a trigger file named as xyz_extract_file_20081201.null (the YYYYMMDD portion would change every day). The wait/wakeup time would be 1 min and the date portion will always be current date (Eg., the trigger file named as xyz_extract_file_20081201.null will be watched on 20081201). The timeout must happen after 8 hours. Could you please help me with a shell script?

Code:
date=$( date +%Y%m%d )
n=0
max=480
while :
do
  sleep 60 & pid=$!
  if [ -f "xyz_extract_file_$date.null" ]
  then
     echo "I'm awake!"
  fi
  n=$(( $n + 1 ))
  [ $n -eq $max ] && break
  wait "$pid"
done

# 3  
Old 12-30-2008
Thanks cfajohnson!
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